document.write( "Question 1171711: Of 288 employees randomly selected from one company, 14.6% of them commute by carpooling. Construct a 90% confidence interval for the true population proportion of all employees who carpool. \n" ); document.write( "
Algebra.Com's Answer #796628 by Boreal(15235)\"\" \"About 
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the half-interval iz z(0.95)*sqrt(p*(1-p)/n)
\n" ); document.write( "=1.645* sqrt (0.146*0.854)/288=0.0342
\n" ); document.write( "The 90%CI is (0.114, 0.178)\r
\n" ); document.write( "\n" ); document.write( "This assumes that 14.6% of 288 is an integer, which it almost is. The actual number is 42/288 but it gives the same result except at the thousandth place.
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