document.write( "Question 1171626: cos(a) =-4/5 and a is in quadrant II and sin(b)=5/13 and b is in quadrant II. Find cos(a+b)
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Algebra.Com's Answer #796609 by MathTherapy(10555)\"\" \"About 
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cos(a) =-4/5 and a is in quadrant II and sin(b)=5/13 and b is in quadrant II. Find cos(a+b)
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cos (a + b) = cos (a) cos (b) - sin (a) sin (b)
\n" ); document.write( "From above, it's obvious that we need cos (b) and sin (a).
\n" ); document.write( "Given \"matrix%281%2C3%2C+cos+%28a%29%2C+%22=%22%2C+%28-+4%29%2F5%29\", and that ∡a is in the 2nd quadrant, we should realize that we're dealing with a 3-4-5 PYTHAGOREAN TRIPLE, which means that \"matrix%281%2C3%2C+sin+%28a%29%2C+%22=%22%2C+3%2F5%29\".
\n" ); document.write( "Likewise, given \"matrix%281%2C3%2C+sin+%28b%29%2C+%22=%22%2C+5%2F13%29\", and that ∡b is in the 2nd quadrant, we should realize that we're dealing with a 5-12-13 PYTHAGOREAN TRIPLE, which means that \"matrix%281%2C3%2C+cos+%28b%29%2C+%22=%22%2C+%28-+12%29%2F13%29\".
\n" ); document.write( "We now have: \n" ); document.write( "
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