document.write( "Question 1171695: Coffee contains caffeine. The half-life of caffeine is 5 hours. This means the amount of caffeine in your bloodstream is reduced by 50% every 5 hours. Suppose you drink a cup of coffee that contains 320 mg of caffeine. How long will it take until there is 5 mg of caffeine left in your bloodstream? \n" ); document.write( "
Algebra.Com's Answer #796607 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The phrasing \"is reduced by 50%\" is the same as \"reduced by half\". Every 5 hours, the amount of caffeine is reduced by half.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you started with 320 mg of caffeine, then you'll have 320/2 = 160 mg of caffeine after 5 hours. Then you'll have 160/2 = 80 mg after another 5 hours (5+5 = 10 total so far)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We keep dividing the amount in half and keep track how much time has passed by (along with the number of half-lives)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A table is useful for this sort of thing. \n" ); document.write( "
\n" ); document.write( "The time value is in hours, and the amount represents the amount of caffeine in mg.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The table shows at time 30 hours, there's exactly 5 mg of caffeine left in the bloodstream. \n" ); document.write( "This happens after 6 half-lives have occurred.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An algebraic approach\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of half-lives that pass by \n" ); document.write( "y = amount of caffeine left over in the bloodstream\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation tying together x and y is \n" ); document.write( "y = 320*(0.5)^x \n" ); document.write( "where 1/2 = 0.5 represents the multiplier indicating a 50% reduction\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We could guess-and-check by plugging in random values of x to see if we get y = 5. \n" ); document.write( "But let's solve for x using algebra\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in y = 5 and use logs to isolate the exponent \n" ); document.write( "y = 320*(0.5)^x \n" ); document.write( "5 = 320*(0.5)^x \n" ); document.write( "5/320 = (0.5)^x \n" ); document.write( "0.015625 = (0.5)^x \n" ); document.write( "log(0.015625) = log( (0.5)^x ) \n" ); document.write( "log(0.015625) = x*log( 0.5 ) \n" ); document.write( "x*log( 0.5 ) = log(0.015625) \n" ); document.write( "x = log(0.015625)/log(0.5) \n" ); document.write( "x = 6 \n" ); document.write( "This helps confirm the half-life we got earlier with the table.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another confirmation method is to plug x = 6 into the equation \n" ); document.write( "y = 320*(0.5)^x \n" ); document.write( "y = 320*(0.5)^6 \n" ); document.write( "y = 320*0.015625 \n" ); document.write( "y = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 6 half-lives occurring mean 5x = 5*6 = 30 hours have passed by (since each half-life is 5 hours).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 30 hours \n" ); document.write( " \n" ); document.write( " |