document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171663>Question 1171663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the interest charged on a loan of Php10,900 for 3 years at 7% compounded semiannually. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796582 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The amount at the end of the three years is 10900(1+(0.07/2))^6=13398.88<BR>\n" );
document.write( "that means the interest was 2498.88 Php<BR>\n" );
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document.write( "Also (1+0.035)^6-1 multiplied by the original principal. </SPAN>\n" );
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