document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171476>Question 1171476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Richey can sell 36 picture frames each month if she charges $18 each. She estimates that for each $3 increase in price, she will sell 3 fewer frames. <BR>\n" );
document.write( "Step 1 of 2 :  Find the price that will yield the maximum revenue.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796518 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (18+3x)(36-3x)=revenue ,where x is the number of increases of $3 in price.<BR>\n" );
document.write( "648+54x-9x^2=revenue<BR>\n" );
document.write( "maximize when x=-b/2a=-54/-18 or 3<BR>\n" );
document.write( "$27 is the price at maximum revenue<BR>\n" );
document.write( "27  is the numbers of frames sold for maximum revenue.<BR>\n" );
document.write( "The answer is $27, the maximum revenue is $729.\r<BR>\n" );
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