document.write( "Question 1171608: Word problems are my weakness, please help\r
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document.write( "Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets cost $30. For one performance, there were 40 tickets sold in all, and the total amount paid for them was $1325. How many tickets of each type were sold? \n" );
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Algebra.Com's Answer #796511 by Boreal(15235) You can put this solution on YOUR website! number equation Advance=A;Same day=S \n" ); document.write( "we know A+S=40 \n" ); document.write( "so S=40-A (can also say A=40-S, but use only one form) \n" ); document.write( "money equation is 35A+30S=1325 \n" ); document.write( "substitute 40-A for S \n" ); document.write( "so 35A+30(40-A)=1325 \n" ); document.write( "35+1200-30A=1325 \n" ); document.write( "5A=125 \n" ); document.write( "A=25 tickets or $875 total \n" ); document.write( "S=15 tickets or $450 total \n" ); document.write( " |