document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171541>Question 1171541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2 times a number is decreased by 9, the principal square root of this difference is 6 less than the number. Find the numbers (s)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796510 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 2 times a number is decreased by 9, the principal square root of this difference is 6 less than the number.<BR>\n" );
document.write( " Find the numbers (s)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The way I see this<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282n-9%29+=+n+-+6 ALIGN=MIDDLE  ALT=\"sqrt%282n-9%29+=+n+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2n+-+9+=+%28n-6%29%5E2 ALIGN=MIDDLE  ALT=\"2n+-+9+=+%28n-6%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "FOIL (n-6)(n-6)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2n+-+9+=+n%5E2+-+12n+%2B+36 ALIGN=MIDDLE  ALT=\"2n+-+9+=+n%5E2+-+12n+%2B+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "combine like terms on the right<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+n%5E2+-+12n+-+2n+%2B+36+%2B+9 ALIGN=MIDDLE  ALT=\"0+=+n%5E2+-+12n+-+2n+%2B+36+%2B+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a quadratic equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=n%5E2+-+14n+%2B+45+=+0 ALIGN=MIDDLE  ALT=\"n%5E2+-+14n+%2B+45+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Factors to<BR>\n" );
document.write( "(n-5)(n-9) = 0<BR>\n" );
document.write( "Two solutions<BR>\n" );
document.write( "n = 5<BR>\n" );
document.write( "n = 9<BR>\n" );
document.write( "Check both in the original equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%285%29-9%29+=+5+-+6 ALIGN=MIDDLE  ALT=\"sqrt%282%285%29-9%29+=+5+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2810-9%29+=+5+-+6 ALIGN=MIDDLE  ALT=\"sqrt%2810-9%29+=+5+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%281%29+=+-1 ALIGN=MIDDLE  ALT=\"sqrt%281%29+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%289%29-9%29+=+9+-+6 ALIGN=MIDDLE  ALT=\"sqrt%282%289%29-9%29+=+9+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289%29+=+3 ALIGN=MIDDLE  ALT=\"sqrt%289%29+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I think the only real solution is n=9<BR>\n" );
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