document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109180>Question 109180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> fugita can complete the assembly of 50 widgest in 6 days.  obn can complete the same job in 8 days.  how many days will it take to complet the project if fugita and obn work together?   I have tried the following \r<BR>\n" );
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document.write( "6(50) = 8(50) <BR>\n" );
document.write( "300 + 400 = 700/14 = 50   \r<BR>\n" );
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document.write( "HELP!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79651 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "AT LEAST YOU GAVE IT A SHOT!!  TRY TO FOLLOW MY APPROACH:\r<BR>\n" );
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document.write( "Let x=number of days it takes both working together to complete the project\r<BR>\n" );
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document.write( "Fugita works at the rate of 50/6 widgets per day (For example, if it takes him 10 days to do 10 cars, then he can do 10/10 or 1 car per day, right?) <BR>\n" );
document.write( "Obn works at the rate of 50/8 widgets per day\r<BR>\n" );
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document.write( "Together they work at the rate of 50/6+50/8 widgets per day\r<BR>\n" );
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document.write( "50/6=200/24 and<BR>\n" );
document.write( "50/8=150/24 <BR>\n" );
document.write( "so<BR>\n" );
document.write( "50/6+50/8=200/24+150/24=350/24=175/12 widgets per day.  So our equation to solve is:\r<BR>\n" );
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document.write( "(175/12)x=50  multiply both sides by 12\r<BR>\n" );
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document.write( "175x=600 divide both sides by 175<BR>\n" );
document.write( "x=3.4286 days-------------------------------number of days it takes with both working together\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "In 3.4286 days, Fugita can build (50/6)*3.4286 or 28.5714 widgets<BR>\n" );
document.write( "In 3.4286 days, Obn can build (50/8)*3.4286 or 21.42875 widgets\r<BR>\n" );
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document.write( "28.5714+21.42875=50<BR>\n" );
document.write( "~50=50\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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