document.write( "Question 109160: Taxi A travels 12mph faster than taxi B. Taxi A travels 140 miles in the same time it takes taxi B to travel 108 miles. Find the speed of each taxi. \n" ); document.write( "
Algebra.Com's Answer #79650 by ptaylor(2198) You can put this solution on YOUR website! \n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt;t=d/r and r=d/t\r \n" ); document.write( "\n" ); document.write( "Let r=rate of taxi B \n" ); document.write( "Then r+12=rate of taxi A\r \n" ); document.write( "\n" ); document.write( "Time it takes taxi A to travel 140 mi=140/(r+12) \n" ); document.write( "Time it takes taxi B to travel 108 mi=108/r\r \n" ); document.write( "\n" ); document.write( "Now we are told that the above two times are equal. So:\r \n" ); document.write( "\n" ); document.write( "140/(r+12)=108/r multiply both sides by r(r+12) to get rid of fractions. (Note: cross-multiplying yields the same result)\r \n" ); document.write( "\n" ); document.write( "140r=108(r+12) get rid of parens (distributive law)\r \n" ); document.write( "\n" ); document.write( "140r=108r+1296 subtract 108r from both sides\r \n" ); document.write( "\n" ); document.write( "140r-108r=108r+1296-108r collect like terms\r \n" ); document.write( "\n" ); document.write( "32r=1296 divide both sides by 32\r \n" ); document.write( "\n" ); document.write( "r=40.5 mph-----------------------------------speed of taxi B \n" ); document.write( "r+12=40.5+12=52.5 mph-------------------------speed of taxi A\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "140/(52.5)=108/(40.5)\r \n" ); document.write( "\n" ); document.write( "2.666666667=2.666666667\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |