document.write( "Question 109105: The length of a rectangle is four times its width. Its perimeer is 90 m. Find its dimentions. Use P= 2l+2w. \n" ); document.write( "
Algebra.Com's Answer #79649 by HyperBrain(694)\"\" \"About 
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Let l=length
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\n" ); document.write( "\n" ); document.write( "IF length of a rectangle is four times its width, then \"l=4w\"\r
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\n" ); document.write( "\n" ); document.write( "The perimeter,\r
\n" ); document.write( "\n" ); document.write( "\"P=2l%2B2w\"\r
\n" ); document.write( "\n" ); document.write( "becomes\r
\n" ); document.write( "\n" ); document.write( "\"P=2%284w%29%2B2w=%282%2A4%29w%2B2w=8w%2B2w=10w\"\r
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\n" ); document.write( "\n" ); document.write( "But, the perimeter is 90 m . SO,\r
\n" ); document.write( "\n" ); document.write( "\"10w=90\"
\n" ); document.write( "\"w=10\"
\n" ); document.write( "Thus, the width measures 10 m long\r
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\n" ); document.write( "\n" ); document.write( "again,\r
\n" ); document.write( "\n" ); document.write( "\"l=4w=4%2A10=40\"\r
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\n" ); document.write( "\n" ); document.write( "Thus, the length measures 40 m long\r
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\n" ); document.write( "\n" ); document.write( "Power up,
\n" ); document.write( "HyperBrain!
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