document.write( "Question 1171585: The complex numbers z and w satisfy |z| = |w| = 1 and zw is not equal to -1.
\n" ); document.write( "(a) Prove that \overline{z} = {1}/{z} and \overline{w} = {1}/{w}.
\n" ); document.write( "(b) Prove that {z + w}/{zw + 1} is a real number.
\n" ); document.write( "Can you please explain in detail? I'm super confused, can someone please help? Thank you so much.
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Algebra.Com's Answer #796489 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "z = a+bi
\n" ); document.write( "w = c+di
\n" ); document.write( "where a,b,c,d are real numbers and i = sqrt(-1) or i^2 = -1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since |z| = 1, this means
\n" ); document.write( "|z| = sqrt(a^2+b^2)
\n" ); document.write( "1 = sqrt(a^2+b^2)
\n" ); document.write( "1^2 = (sqrt(a^2+b^2))^2
\n" ); document.write( "1 = a^2 + b^2
\n" ); document.write( "a^2 + b^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "Through similar algebraic steps, we can say,
\n" ); document.write( "|w| = 1
\n" ); document.write( "leads to
\n" ); document.write( "c^2 + d^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "---------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Using our definition of z, let's find 1/z
\n" ); document.write( "\"z+=+a%2Bbi\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+1%2F%28a%2Bbi%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%281%2F%28a%2Bbi%29%29%2A%28%28a-bi%29%2F%28a-bi%29%29\" This step is done to turn the denominator into a real number.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%281%2A%28a-bi%29%29%2F%28%28a%2Bbi%29%2A%28a-bi%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%28a-bi%29%2F%28a%5E2-%28bi%29%5E2%29\" Difference of squares rule\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%28a-bi%29%2F%28a%5E2-b%5E2i%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%28a-bi%29%2F%28a%5E2-b%5E2%28-1%29%29\" Plug in i^2 = -1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%28a-bi%29%2F%28a%5E2%2Bb%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+%28a-bi%29%2F%281%29\" Plug in a^2+b^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fz+=+a-bi\"\r
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\n" ); document.write( "\n" ); document.write( "\r
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\n" ); document.write( "\n" ); document.write( "This proves that \"1%2Fz\" is equal to the complex conjugate of \"z\"\r
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\n" ); document.write( "\n" ); document.write( "The steps to proving \"1%2Fw\" is equal to the conjugate of \"w\" are effectively the same as shown above. I'll let you do this part.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We'll use the fact that along with in part (b).\r
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\n" ); document.write( "\n" ); document.write( "==========================================================================\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "x = complex conjugate of z = a-bi
\n" ); document.write( "y = complex conjugate of w = c-di
\n" ); document.write( "I'm using x and y instead of the overbar notation because I think the overbar notation is a bit clunky, especially when mixed with fraction bars.\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "z+x = (a+bi)+(a-bi) = 2a
\n" ); document.write( "w+y = (c+di)+(c-di) = 2c
\n" ); document.write( "both are real values. \r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Furthermore,
\n" ); document.write( "z*x = 1
\n" ); document.write( "w*y = 1
\n" ); document.write( "was proven earlier in part (a), just with different notation.
\n" ); document.write( "This indicates that zx*wy = 1*1 = 1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now if
\n" ); document.write( "z = a+bi
\n" ); document.write( "w = c+di
\n" ); document.write( "Then,
\n" ); document.write( "z*w = (a+bi)*(c+di)
\n" ); document.write( "z*w = a*(c+di)+bi*(c+di)
\n" ); document.write( "z*w = ac+adi+bci+bdi^2
\n" ); document.write( "z*w = ac+adi+bci+bd(-1)
\n" ); document.write( "z*w = ac+adi+bci-bd
\n" ); document.write( "z*w = (ac-bd)+(adi+bci)
\n" ); document.write( "z*w = (ac-bd)+(ad+bc)i\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Through very similar steps we can say,
\n" ); document.write( "x = a-bi
\n" ); document.write( "y = c-di
\n" ); document.write( "x*y = (ac-bd)-(ad+bc)i\r
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\n" ); document.write( "\n" ); document.write( "As you can see:
\n" ); document.write( "zw+xy = [(ac-bd)+(ad+bc)i] + [(ac-bd)-(ad+bc)i]
\n" ); document.write( "zw+xy = [(ac-bd)+(ac-bd)]+[(ad+bc)i-(ad+bc)i]
\n" ); document.write( "zw+xy = [2(ac-bd)]+[0(ad+bc)i]
\n" ); document.write( "zw+xy = 2(ac-bd)+0i
\n" ); document.write( "zw+xy = 2(ac-bd)
\n" ); document.write( "which is a real result\r
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\n" ); document.write( "\n" ); document.write( "To summarize everything so far for part (b), we can add any complex number to its conjugate to get a real result. Similarly, we can multiply any complex number with its conjugate to get a real result. Lastly, zw+xy sorta involves both concepts going on at once which means zw+xy is also a real number.\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We build up those statements to be able to say the following\r
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\n" ); document.write( "\n" ); document.write( "\"%28z%2Bw%29%2F%28zw%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%28%28zw%2B1%29%2A%28xy%2B1%29%29\" Multiply numerator and denominator by xy+1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%28%28zw%2Axy%29%2Bzw%2Bxy%2B1%29\" Expand out the denominator\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%28%28zx%2Awy%29%2B%28zw%2Bxy%29%2B1%29\" Group up the terms like such\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%281%2B%28zw%2Bxy%29%2B1%29\" Plug in zx*wy = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%281%2B2%28ac-bd%29%2B1%29\" Plug in zw+xy = 2(ac-bd)\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%282%28ac-bd%29%2B2%29\" Simplify\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The denominator 2(ac-bd)+2 is some real number. Let's expand out the numerator and see what we get\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bw%29%28xy%2B1%29%29%2F%282%28ac-bd%29%2B2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28zxy%2Bz%2Bwxy%2Bw%29%2F%282%28ac-bd%29%2B2%29\" FOIL the numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%28zx%2Ay%2Bz%2Bwy%2Ax%2Bw%29%2F%282%28ac-bd%29%2B2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281y%2Bz%2B1x%2Bw%29%2F%282%28ac-bd%29%2B2%29\" Plug in zx = 1 and wy = 1. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28y%2Bz%2Bx%2Bw%29%2F%282%28ac-bd%29%2B2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%28z%2Bx%29%2B%28w%2By%29%29%2F%282%28ac-bd%29%2B2%29\" Group up the conjugate pairs\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282a%2B2c%29%2F%282%28ac-bd%29%2B2%29\" Plug in z+x = 2a and w+y = 2c\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The numerator 2a+2c is a real number.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We could divide every term by 2 to simplify further, but at this point we're effectively done with the proof. \r
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\n" ); document.write( "\n" ); document.write( "Both the numerator and denominator are real values, so overall \"%28z%2Bw%29%2F%28zw%2B1%29\" is a real number.\r
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\n" ); document.write( "\n" ); document.write( "Note: The condition \"zw+%3C%3E+-1\" is to prevent the denominator \"zw%2B1\" from being zero. \r
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\n" ); document.write( "\n" ); document.write( "Further Reading:
\n" ); document.write( "https://math.stackexchange.com/questions/427663/prove-if-z-w-1-and-1zw-neq-0-then-zw-over-1zw-is-a-real
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