document.write( "Question 109230: One number is 12 more than a another. the sum of the smallest number and twice the larger number is 39. find the larger number\r
\n" ); document.write( "\n" ); document.write( "x + 12 = y
\n" ); document.write( "x + 2(y)= 39\r
\n" ); document.write( "\n" ); document.write( "Am I on the right track for solving this problem?
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Algebra.Com's Answer #79646 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You set it up perfectly\r
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\n" ); document.write( "\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2y=39\"
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\n" ); document.write( "\n" ); document.write( "\"x%2B2%28x%2B12%29=39\" Plug in \"y=x%2B12\" into the first equation. In other words, replace each \"y\" with \"x%2B12\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2x%2B24=39\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B24=39\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"3x=39-24\"Subtract 24 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=15\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2815%29%2F%283%29\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=5\", we can plug this into \"y=x%2B12\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%285%29%2B12\" Substitute \"5\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=17\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=5\" and \"y=17\"\r
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\n" ); document.write( "\n" ); document.write( "So our two numbers are 5 and 17
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