document.write( "Question 1171551: Jacob and Kayla are selling cheesecake for a school fundraiser. Customers can buy pecan cheesecake. Jacob sold 2 pecan cheesecake and 4 apple cheesecake for a total of 96$. Kayla Sold 8 pecan cheesecake and 4 apple cheesecake for a total of 156$ . What is the cost each of one pecan cheesecake and one apple cheesecake? \n" ); document.write( "
Algebra.Com's Answer #796447 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The difference between the two sales is 6 additional pecan cheesecakes, for a cost difference of $60. So each pecan cheesecake costs $60/6 = $10.

\n" ); document.write( "Then using either of the sales and the $10 cost of each pecan cheesecake to determine the cost of each apple cheesecake.

\n" ); document.write( "Algebraically....

\n" ); document.write( "(1) 2p+4a = 96
\n" ); document.write( "(2) 8p+4a = 156

\n" ); document.write( "Subtract (1) from (2):
\n" ); document.write( "6p = 60
\n" ); document.write( "p=60/6=10

\n" ); document.write( "Substitute p=10 in either (1) or (2):
\n" ); document.write( "20+4a = 96
\n" ); document.write( "4a = 76
\n" ); document.write( "a = 76/4 = 19

\n" ); document.write( "ANSWERS: $10 for each pecan cheesecake; $19 for each apple cheesecake

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