document.write( "Question 1171456: Given: x^2+y^2-6x+8y-11=0.
\n" ); document.write( "1. Find the equation of the circle in standard form.
\n" ); document.write( "2. Find the center and the radius.
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Algebra.Com's Answer #796377 by Theo(13342)\"\" \"About 
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regroup the terms to get:
\n" ); document.write( "(x^2 - 6x) + (y^2 + 8y) - 11 = 0
\n" ); document.write( "complete the squares to get:
\n" ); document.write( "(x-3)^2 - 9 + (y+4)^2 - 16 - 11 = 0
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "(x-3)^2 + (y+4)^2 -36 = 0
\n" ); document.write( "add 36 to both sides of the equation to get:
\n" ); document.write( "(x-3)^2 + (y+4)^2 = 36
\n" ); document.write( "that's your equation in standard form of a circle.
\n" ); document.write( "the center is at (3,-4) and the radius is equal to sqrt(36) = 6
\n" ); document.write( "here's the graph of both equations.\r
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\n" ); document.write( "\n" ); document.write( "since they are identical, they make the same figure on the graph.
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