document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171403>Question 1171403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Whitney has 20 coins in her purse.  Some are quarters and some are dimes.  The total value of the coins is $3.35.  How many quarters does Whitney have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796376 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A quick mental solution method, if formal algebra is not required....<br><BR>\n" );
document.write( "(1) Imagine 20 coins that are all dimes; the value would be $2.00, which is $1.35 less than the actual total.<BR>\n" );
document.write( "(2) Now imagine switching dimes for quarters, one at a time.  Each time, the number of coins stays the same, while the value of the coins increases by 25-10 = 15 cents.<BR>\n" );
document.write( "(3) The number of times you need to do that to make up the additional $1.35 (135 cents) is 135/15 = 9.<BR>\n" );
document.write( "(4) Therefore, 9 of the coins are quarters.<br><BR>\n" );
document.write( "ANSWER: 9 quarters (and 11 dimes)<br><BR>\n" );
document.write( "CHECK: 9(25)+11(10) = 225+110 = 335<br><BR>\n" );
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