document.write( "Question 1171405: The total calories gained from eating 2 oranges and 3 strawberries is 112 calories. On
\n" ); document.write( "the other hand, the total calories gained from eating 3 oranges and 4 strawberries is 165
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Algebra.Com's Answer #796360 by ikleyn(52914) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "x for oranges' calories\r\n" );
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document.write( "y for strawberries' calories\r\n" );
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document.write( "    2x + 3y = 112    (1)\r\n" );
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document.write( "    3x + 4y = 165    (2)\r\n" );
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document.write( "Multiply first equation by 3 (both sides) and the second equation by 2. You will get\r\n" );
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document.write( "    6x + 9y = 336    (3)\r\n" );
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document.write( "    6x + 8y = 330    (4)\r\n" );
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document.write( "Subtract equation (4) from equation (5).  The terms \"6x\" will cancel each other\r\n" );
document.write( "and you will get single equation for the unknown y only\r\n" );
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document.write( "          9y - 8y = 336 - 330\r\n" );
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document.write( "             y    = 6.\r\n" );
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document.write( "So, we have 6 calories for each strawberry.\r\n" );
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document.write( "Now substitute y= 6 into very first equation. You will get\r\n" );
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document.write( "    2x + 3*6 = 112\r\n" );
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document.write( "    2x       = 112 - 18 =   94\r\n" );
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document.write( "     x                  = 94/2 = 47.\r\n" );
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document.write( "ANSWER.  47 calories for each orange and 6 calories per strawberry.  \r\n" );
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document.write( "CHECK.  Make checking on your own by substituting the found values into the original equations.\r\n" );
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