document.write( "Question 109218: y= x + 3
\n" ); document.write( "y= 4x -3 \r
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\n" ); document.write( "\n" ); document.write( "solve each system using substitution
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Algebra.Com's Answer #79636 by stanbon(75887)\"\" \"About 
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y= x + 3
\n" ); document.write( "y= 4x -3
\n" ); document.write( "----------
\n" ); document.write( "x+3 = 4x-3
\n" ); document.write( "3x=6
\n" ); document.write( "x = 2
\n" ); document.write( "-------
\n" ); document.write( "Substitute into y = x+3 to solve for y:
\n" ); document.write( "y= 2+3
\n" ); document.write( "y = 5
\n" ); document.write( "============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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