document.write( "Question 1171400: I am having trouble with understanding this question:\r
\n" ); document.write( "\n" ); document.write( "The sum of three numbers is 40. The second number is twice the first number. The sum of the first two numbers is 2 more than the third number. What are the three numbers?\r
\n" ); document.write( "\n" ); document.write( "So far, I've worked out:
\n" ); document.write( "x+y+z=10
\n" ); document.write( "y=2x
\n" ); document.write( "x+y=z+2 \n" ); document.write( "

Algebra.Com's Answer #796359 by ikleyn(52795) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            With my magic lamp, I will show it to you now.\r
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document.write( "Let x be the first number.\r\n" );
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document.write( "Then the second number is 2x, according to the condition.\r\n" );
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document.write( "Then the third number is  (40-x-2x) = 40-3x.\r\n" );
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document.write( "The sum of the first two numbers is 2 more than the third number\r\n" );
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document.write( "    x + 2x = (40-3x) + 2\r\n" );
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document.write( "Solve this simple equation\r\n" );
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document.write( "    x + 2x + 3x = 40+2\r\n" );
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document.write( "        6x      = 42\r\n" );
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document.write( "         x      = 42/6 = 7.\r\n" );
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document.write( "ANSWER.  The first number is 7;  the second number is 2*7 = 14, and the third number is  40 - 7 - 14 = 19.\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is how this problem SHOULD be treated, solved, explained and taught.\r
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\n" ); document.write( "\n" ); document.write( "The problem is designed, intended and expected to be solved in this way.\r
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\n" ); document.write( "\n" ); document.write( "Any other way is LAME.\r
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\n" ); document.write( "\n" ); document.write( "I know it and know this way, because I have my magic lamp.\r
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\n" ); document.write( "\n" ); document.write( "A miracle is the fact that the problem is solved using only one single unknown and one single equation.\r
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\n" ); document.write( "\n" ); document.write( "It is intended to teach 6-th grade (7-th grade ?) students in this way.\r
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