document.write( "Question 1171383: Let \"+l_1+\" and \"+l_2+\" two parallel lines. We choose \"+8+\" points on \"+l_1+\" and \"+7+\" on \"+l_2+\". Then all the market points on \"+l_1+\" are joined with the market points on \"+l_2+\". How many points are obtained as an intersection (that are not in \"+l_1+\" nor in \"+l_2+\") of the traced segments?\r
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Algebra.Com's Answer #796357 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The problem  ASSUMES  that the points are in  \"GENERAL  PLACEMENT\",  which means that among the connecting lines\r
\n" ); document.write( "\n" ); document.write( "there are  NO  parallel lines and that the intersection points are  ALL  DIFFERENT  (there is no coinciding intersection points).\r
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document.write( "In all, there are  8*7 different lines.\r\n" );
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document.write( "Every two different lines have one intersection point on the plane (inside  the strip between the lines or outside it).\r\n" );
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document.write( "The intersection points that lie on the given parallel lines are included in this counting.\r\n" );
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document.write( "Thus the number of intersection points is equal to the number of pairs of different lines,\r\n" );
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document.write( "which is the number of combinations of 56 lines taken 2 at a time  \"C%5B56%5D%5E2\" = \"%2856%2A55%29%2F2\" = 1540.    ANSWER\r\n" );
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document.write( "ANSWER.  The number of intersection points on the plane is  1540.\r\n" );
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document.write( "         The intersection points on the parallel lines are included.\r\n" );
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