document.write( "Question 1171383: Let and
two parallel lines. We choose
points on
and
on
. Then all the market points on
are joined with the market points on
. How many points are obtained as an intersection (that are not in
nor in
) of the traced segments?\r
\n" );
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document.write( "I´ve solved the problem by doing all the lines and I got intersections, so, I´m looking for a solution with out making all of them. \n" );
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Algebra.Com's Answer #796357 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The problem ASSUMES that the points are in \"GENERAL PLACEMENT\", which means that among the connecting lines\r \n" ); document.write( "\n" ); document.write( "there are NO parallel lines and that the intersection points are ALL DIFFERENT (there is no coinciding intersection points).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "In all, there are 8*7 different lines.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Every two different lines have one intersection point on the plane (inside the strip between the lines or outside it).\r\n" ); document.write( "\r\n" ); document.write( "The intersection points that lie on the given parallel lines are included in this counting.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the number of intersection points is equal to the number of pairs of different lines,\r\n" ); document.write( "\r\n" ); document.write( "which is the number of combinations of 56 lines taken 2 at a time\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |