document.write( "Question 1171400: I am having trouble with understanding this question:\r
\n" ); document.write( "\n" ); document.write( "The sum of three numbers is 40. The second number is twice the first number. The sum of the first two numbers is 2 more than the third number. What are the three numbers?\r
\n" ); document.write( "\n" ); document.write( "So far, I've worked out:
\n" ); document.write( "x+y+z=10
\n" ); document.write( "y=2x
\n" ); document.write( "x+y=z+2 \n" ); document.write( "
Algebra.Com's Answer #796356 by Alan3354(69443)\"\" \"About 
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The sum of three numbers is 40. The second number is twice the first numxber. The sum of the first two numbers is 2 more than the third number. What are the three numbers?\r
\n" ); document.write( "\n" ); document.write( "So far, I've worked out:
\n" ); document.write( "x+y+z=40
\n" ); document.write( "y=2x
\n" ); document.write( "x+y=z+2
\n" ); document.write( "====================
\n" ); document.write( "Your eqns are correct except for the sum = 10
\n" ); document.write( "Sub for y in the 1st and 3rd eqns.
\n" ); document.write( "---
\n" ); document.write( "x + 2x + z = 40 ---> 3x + z = 40
\n" ); document.write( "x + 2x = z + 2 ---> 3x = z + 2 --> 3x - z = 2
\n" ); document.write( "------------
\n" ); document.write( "3x + z = 40
\n" ); document.write( "3x - z = 2
\n" ); document.write( "------------------- Add
\n" ); document.write( "6x = 42
\n" ); document.write( "x = 7
\n" ); document.write( "--------
\n" ); document.write( "Solve for y, then solve for z
\n" ); document.write( " \n" ); document.write( "
\n" );