document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171254>Question 1171254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average price of the Panther convertible is P1.68M, with a standard deviation of P168, 000. The average price of the Suburban station wagon is P840, 000 with a standard deviation of P84, 000. Compare the variability of the two prices. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796349 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratio of their sd s is 168K/1.68M =0.1 for the first<BR>\n" );
document.write( "and 84K/84000 K or 0.1 for the second.<BR>\n" );
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document.write( "The variability is twice as much for the first as it is for the second, but the second is 1/2 the value of the mean as the first, so the ratio of the variability to the mean is the same for both.\r<BR>\n" );
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document.write( "Since the variance is the sd ^2, there is a four-fold difference in the variance and a two-fold difference in the sd for a mean that is twice is much. Since the variance increases with the square, unlike the mean, this is consistent with the variability's (not variance) being the same. </SPAN>\n" );
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