document.write( "Question 1171376: ​% 51 of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.
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Algebra.Com's Answer #796337 by Boreal(15235)\"\" \"About 
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a. exactly 5 is 10C5*0.51^5*0.49^5=0.2456 also 2ndVARSbinompdf(10,0.51,5)ENTER
\n" ); document.write( "b. at least 6 is for 6 through 10=0.4018 1-2ndVARSbinomcdf(10,0.51,5)ENTER, since calculator does binomial from the left, have to subtract the left side from 1 to get the right side
\n" ); document.write( "c. fewer than 4 is 0.1560
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