document.write( "Question 1171312: A female patient has had her red blood cell count tested on 6 occasions. A mean of 4.4
\n" ); document.write( "with sample standard deviation, s, of 0.28 was found. Generally, healthy, female adults
\n" ); document.write( "have a red blood cell count of 4.8. Conduct a hypothesis test to determine if the red
\n" ); document.write( "blood cell count for this patient is lower than normal. (Use a = 0.05.)
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\n" ); document.write( "Hypothesis:
\n" ); document.write( "H0: mu = 4.8
\n" ); document.write( "H1: mu < 4.8
\n" ); document.write( "Left tailed test\r
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\n" ); document.write( "\n" ); document.write( "alpha = 0.05\r
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\n" ); document.write( "\n" ); document.write( "n = 6 is the sample size
\n" ); document.write( "Because n < 30 and sigma is not known, this means we must use a T test. Sigma is the population standard deviation.\r
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\n" ); document.write( "\n" ); document.write( "While the population standard deviation is not known, the population mean (mu) is known. In this case, it is mu = 4.8, which is how the hypothesis is formed above.\r
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\n" ); document.write( "\n" ); document.write( "For the female patient, the samples lead to
\n" ); document.write( "xbar = sample mean = 4.4
\n" ); document.write( "s = sample standard deviation = 0.28\r
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\n" ); document.write( "\n" ); document.write( "The standard error (SE) is
\n" ); document.write( "SE = s/sqrt(n)
\n" ); document.write( "SE = 0.28/sqrt(6)
\n" ); document.write( "SE = 0.11430952132989\r
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\n" ); document.write( "\n" ); document.write( "The T test statistic is
\n" ); document.write( "t = (xbar - mu)/(SE)
\n" ); document.write( "t = (4.4 - 4.8)/(0.11430952132989)
\n" ); document.write( "t = -3.49927106111857
\n" ); document.write( "t = -3.499271\r
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\n" ); document.write( "\n" ); document.write( "Use a T cdf function on your calculator to find that
\n" ); document.write( "P(T < -3.499271) = 0.0086 approximately when df = n-1 = 5
\n" ); document.write( "df = degrees of freedom
\n" ); document.write( "So the p value is approximately 0.0086
\n" ); document.write( "This p value is smaller than alpha = 0.05, so we reject the null and conclude that mu < 4.8\r
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\n" ); document.write( "\n" ); document.write( "Another way to reject the null is to notice that the test statistic (-3.499271) is to the left of the T critical value (-2.015) when alpha = 0.05 and df = 5. Use a calculator or a T table to find the T critical value. So this test statistic is in the rejection region.\r
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\n" ); document.write( "\n" ); document.write( "Interpretation: Her mean red blood cell count is less than 4.8, which means it's lower than normal.
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