document.write( "Question 1171322: A stage theater sold tickets for $ 300. Senior citizens received a discount of 30%, and paid only $ 210. On the initial showing, the theater sold 250 tickets and registered a total of $ 66,000. How many of each type tickets were sold? \n" ); document.write( "
Algebra.Com's Answer #796270 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First, a typical algebraic setup for solving the problem.... \n" ); document.write( "x = number of senior tickets \n" ); document.write( "250-x = number of regular tickets \n" ); document.write( "Total ticket sales was $66,000: \n" ); document.write( " \n" ); document.write( "Solve for x using basic algebra; then use that value to find the numbers of each kind of ticket. I leave it to you to finish solving the problem by that method. \n" ); document.write( "Here is an alternative method for solving \"mixture\" problems like this that I prefer, because (for me) I get to the answer faster and with less effort. \n" ); document.write( "(1) Determine that the average ticket price, for $66,000 from 250 tickets, is $66000/250 = $264. \n" ); document.write( "(2) Look at the three prices $210, $264, and $300 on a number line and use simple calculations to determine that $264 is 54/90 = 6/10 = 3/5 of the way from $210 to $300. \n" ); document.write( "(3) That means 3/5 of the tickets were the higher priced tickets. \n" ); document.write( "ANSWER: 3/5 of 250 tickets, or 150 tickets, were regular tickets; the other 100 tickets were senior tickets. \n" ); document.write( "CHECK: 150(300)+100(210) = 45000+21000 = 66000 \n" ); document.write( " \n" ); document.write( " |