document.write( "Question 1171302: The area of a rectangular pool is 300 square feet. The length of the pool is 5 feet more than the width of the pool. What is the length of the pool? (Can I see how you solver it please?) \n" ); document.write( "
Algebra.Com's Answer #796239 by ikleyn(52800)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "x for the length,\r\n" );
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document.write( "(x-5) for the width.\r\n" );
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document.write( "The area equation is\r\n" );
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document.write( "    x*(x-5) = 300.\r\n" );
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document.write( "It is your basic equation to be solved.\r\n" );
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document.write( "Reduce it to the standard form of a quadratic equation\r\n" );
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document.write( "    x^ 2 - 5x - 300 = 0     (*)\r\n" );
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document.write( "From this point, you can solve this equation in 2 (two) ways.\r\n" );
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document.write( "One way is to apply the quadratic formula\r\n" );
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document.write( "    \"x%5B1%2C2%5D\" = \"%285+%2B-+sqrt%285%5E2+%2B+4%2A300%29%29%2F2\" = \"%285+%2B-+sqrt%281225%29%29%2F2\" = \"%285+%2B-+35%29%2F2\",\r\n" );
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document.write( "which gives you two roots x= \"%285+%2B+35%29%2F2\" = \"40%2F2\" = 20  and  x = \"%285+-+35%29%2F2\" = \"-30%2F2\" = -15.\r\n" );
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document.write( "Of these two roots, only positive x = 20 makes sense.\r\n" );
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document.write( "The other way to solve quadratic equation (*) is to factor its left side\r\n" );
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document.write( "    (x-20)*(x+15) = 0.\r\n" );
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document.write( "It gives the same two roots, of which you chose the positive value x= 20.\r\n" );
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document.write( "So, your ANSWER is: the length of the pool is 20 feet.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems, look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Problems on the area and the dimensions of a rectangle\r
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