document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171200>Question 1171200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many pounds of sugar that costs 1.79 per pound and how many pounds of corn flakes that costs 2.49 per pound must be used tyo create 25 pounds of sugar coated breakfast cereal that sells for 2.21 per pound<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #796122 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=796122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You have two responses that both show basically the same standard algebraic method for solving \"mixture\" problems like this.<br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a different method that will almost always get you to the answer faster and with less effort.<br><BR>\n" );
document.write( "(1) Look at the three per-pound prices on a number line: 1.79, 2.21, and 2.49.<BR>\n" );
document.write( "(2) Determine by simple calculations that 2.21 is 42/70 = 3/5 of the way from 1.79 to 2.49.<BR>\n" );
document.write( "(3) That means 3/5 of the mixture is the higher-priced ingredient.<br><BR>\n" );
document.write( "ANSWER: 3/5 of the total 25 pounds, or 15 pounds, of corn flakes; the other 10 pounds is the sugar.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "15(2.49)+10(1.79) = 37.35+17.90 = 55.25<BR>\n" );
document.write( "25(2.21) = 55.25<br><BR>\n" );
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