document.write( "Question 109173This question is from textbook
\n" ); document.write( ": Please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "x+4 over x^2-3x+2 minus 5 over x^2-4x+3 = x-4 over x^2-5x+6\r
\n" ); document.write( "\n" ); document.write( "I know factoring comes into play but I'm lost.\r
\n" ); document.write( "\n" ); document.write( "Please show me all of your steps so I can understand what I'm doing.\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "

Algebra.Com's Answer #79612 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
[(x+4)/(x^2-3x+2)] - [ 5 /( x^2-4x+3)] = [(x-4)/(x^2-5x+6)]\r
\n" ); document.write( "\n" ); document.write( "Factor where you can to get:
\n" ); document.write( "
\n" ); document.write( "[(x+4)/(x-2)(x-1))] - [ 5 /( x-1)(x-3))] = [(x-4)/(x-6)(x+1)]\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by (x-2)(x-1)(x-3)(x-6)(x+1) to get a mess:\r
\n" ); document.write( "\n" ); document.write( "[(x+4)(x-3)(x-6)(x+1)] -[5(x-2)(x-6)(x+1)] = (x-4)(x-2)(x-1)(x_3)\r
\n" ); document.write( "\n" ); document.write( "I'll let you multiply out this mess and simplify each term.
\n" ); document.write( "Personally, I think this kind of problem is nothing but busy
\n" ); document.write( "work.
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );