document.write( "Question 1171108: According to a survey only 20% of customers who visited tje website of a major retail store made a purchase. random sample sizes of 75 are selected.\r
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document.write( "What proportion of the sample will have between 10% and 40% of customers who will make a purchase after visiting the website \n" );
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Algebra.Com's Answer #796052 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the mean is np=75*0.20=15 \n" ); document.write( "the variance is np(1-p)=15*0.8=12 \n" ); document.write( "the sd is sqrt(V)=3.464 \n" ); document.write( "10% is 7.5 customers (we would consider 8 the bottom number) \n" ); document.write( "40% is 30 customers \n" ); document.write( "with the continuity correction factor, we would use 7.5 and 30.5 for the two values. \n" ); document.write( "z=(7.5-15)/3.464 with z of -2.165 \n" ); document.write( "for 30.5 \n" ); document.write( "z=(30.5-15)/3.464 \n" ); document.write( "=+4.47 \n" ); document.write( "the probability of z's being in between those values is 98.5% \n" ); document.write( " |