document.write( "Question 1171145: Assume you are the owner of a highly-respected law firm. The data below shows the number of cases won each month by two lawyers who work for you.
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document.write( "Lawyer A 42 61 48 54 50 49
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document.write( "Lawyer B 51 23 82 44 79 25\r
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document.write( "On average, would you say that these lawyers are performing equally? Why or why not? If you are looking for a lawyer with a reliable number of wins, which lawyer would you choose?
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document.write( "What statistic did you use to come to that conclusion? Back up your decision with statistical evidence. Do NOT just use the mean or median to explain your answer. \n" );
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Algebra.Com's Answer #796046 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Looking at the data, I suspect the means are similar but the variability is much less in A than for B. The range is only 19 cases for A and 59 cases for B. Then one could use a better measure of variability like the sd.\r \n" ); document.write( "\n" ); document.write( "The means are not only similar but equal. \n" ); document.write( "The std dev for A is 6.38 cases and for B 25.51 cases. This is a large difference. \r \n" ); document.write( "\n" ); document.write( "Means can be the same but the two samples widely different, and here they are. Statistically, were one not careful, a 2-sample t-test would show no difference, but the two sample t-test assumes that the variances of both of the samples are equal, and they are definitely not equal.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |