document.write( "Question 1171129: Paul's age is three years older than Ruth's age. If Emma's age is twice that of Paul's age, find out Paul's age if the total of them two years ago was 51 years. \n" ); document.write( "
Algebra.Com's Answer #796039 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\"Paul's age is three years older than Ruth's age.\" \n" ); document.write( "That statement is nonsense. Paul's age can't be 3 years older than Ruth's age. Each age is a number, presumably in years. One number can't be older than another.... \n" ); document.write( "\"Paul is 3 years older than Ruth.\" \n" ); document.write( "So let Ruth's age be x; then Paul's age is x+3. \n" ); document.write( "\"Emma's age is twice that of Paul's age.\" \n" ); document.write( "So Emma's age is 2(x+3), or 2x+6. \n" ); document.write( "\"The sum of their ages 2 years ago was 51.\" \n" ); document.write( "That means the sum of their ages now is 51+3(2) = 57. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: Paul's age is x+3 = 15. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |