document.write( "Question 109166: find length and width of area 204 perimeter 58 \n" ); document.write( "
Algebra.Com's Answer #79603 by ankor@dixie-net.com(22740)\"\" \"About 
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find length and width of area 204 perimeter 58
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\n" ); document.write( "Let x = length, y = width
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\n" ); document.write( "Perimeter:
\n" ); document.write( "2x + 2y = 58
\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "x + y = 29
\n" ); document.write( "y = (29-x)
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\n" ); document.write( "Area =
\n" ); document.write( "x*y = 204
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\n" ); document.write( "Substitute (29-x) for y:
\n" ); document.write( "x(29-x) = 204
\n" ); document.write( "-x^2 + 29x - 204 = 0; a quadratic equation
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\n" ); document.write( "Multiply by -1, (easier to factor):
\n" ); document.write( "x^2 - 29x + 204 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "(x - 12)(x - 17) = 0
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\n" ); document.write( "x = +12; then y = 17
\n" ); document.write( "or
\n" ); document.write( "x = 17; then y = 12 \n" ); document.write( "
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