document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1171006>Question 1171006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the probability of:\r<BR>\n" );
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document.write( "A. drawing a card that is an ace/a ten/or a red <BR>\n" );
document.write( "B. drawing a Jack/face card<BR>\n" );
document.write( "C. rolling 4 dice and having at least one of them show a 5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795989 by </B><A HREF=/tutors/aboutme.mpl?userid=125004450Sk><B>125004450Sk(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=125004450Sk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A. drawing a card that is an ace or a ten or red. <BR>\n" );
document.write( "   To solve this you must know that there are 52 cards in a standard deck(not including the jokers) and there are 3 face cards in each suit, and there are 13 cards of each suit. The probability of drawing an ace is 4/52 for there are 4 aces in an entire deck of cards. There are 4 tens in each deck of cards so that would equal 4/52. In a deck of cards, there are 26 red cards and 26 black cards. So the probability of drawing a red card is 26/52. Once we figured out the probability of drawing an ace or a ten or red, we combine the answers together. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F52%2B4%2F52%2B26%2F52=34%2F52 ALIGN=MIDDLE  ALT=\"4%2F52%2B4%2F52%2B26%2F52=34%2F52\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Simplify 34/52<BR>\n" );
document.write( "34/52=17/26<BR>\n" );
document.write( "Answer: You have a 17/26 chance of drawing an ace/ten/ or red card.\r<BR>\n" );
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document.write( "B. drawing a Jack/face card<BR>\n" );
document.write( "   As I said before there are 3 face cards in each suit(a jack is among them), so knowing that there are 3 face cards in each suit and we know that there are 4 different suits, we would multiply 4 by 3 and we would get 12 for the number of face cards we have in a deck of cards. Now we have the number of face cards in a deck of cards, so, therefore, we have the answer 12/52. Simplify and we have 3/13 as the final answer for part B.<BR>\n" );
document.write( "Answer: You have a <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F13 ALIGN=MIDDLE  ALT=\"3%2F13\"   DISABLED_style= \"max-width:90%; height:auto;\" > chance of drawing a face card.\r<BR>\n" );
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document.write( "C. rolling 4 dice and having at least one of them show a 5<BR>\n" );
document.write( "   Instead of having 2 as the normal amount of dice, we have 2 pairs of dice(meaning 4 individual die). For the pair of dice, the possibilities would be 36 but since we are dealing with 2 pairs of dice there are a lot more possibilities. Each die has a possibility of 6, when you multiply with 6(due to adding a die) you get 36 so you can have 36 possible outcomes. Multiply that by 6 two more times you get 1296(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2A6%2A6%2A6=1296 ALIGN=MIDDLE  ALT=\"6%2A6%2A6%2A6=1296\"   DISABLED_style= \"max-width:90%; height:auto;\" >). Now since the desired outcome is 5 and we can get 5 out of the 4 die we have so that would give us 4/1296. Simplify and we get 1/324<BR>\n" );
document.write( "Answer: You have a <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F324 ALIGN=MIDDLE  ALT=\"1%2F324\"   DISABLED_style= \"max-width:90%; height:auto;\" > chance of rolling a 5. </SPAN>\n" );
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