document.write( "Question 1171038: If y varies directly as x, and y is 56 when x is 21, find y when x is 74. \n" ); document.write( "

Algebra.Com's Answer #795909 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "If $\"y+\"$ varies directly as $\"x\"$ , then\r
\n" ); document.write( "\n" ); document.write( " $\"y=kx\"$ \r
\n" ); document.write( "\n" ); document.write( " and if $\"y\"$ is $\"56\"$ when $\"x\"$ is $\"+21\"$ ,then \r
\n" ); document.write( "\n" ); document.write( " $\"56=k%2A21\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=56%2F21\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=8%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( "your equation is: \r
\n" ); document.write( "\n" ); document.write( " $\"y=%288%2F3%29x\"$ \r
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\n" ); document.write( "\n" ); document.write( "find $\"y+\"$ when $\"x\"$ is $\"74\"$ :\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"y=%288%2F3%2974\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=592%2F3\"$ -> exact solution\r
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