document.write( "Question 1170979: A ball is thrown off a 30 m cliff at 20 m/s at an angle of 60 degrees above the horizontal
\n" ); document.write( "What is the maximum height of the object?
\n" ); document.write( "What is the total hang time of the ball?
\n" ); document.write( "What is the final velocity of the ball?
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Algebra.Com's Answer #795857 by htmentor(1343)\"\" \"About 
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The total height will be h0 + h, where h0 is the height of the cliff
\n" ); document.write( "We can use the formula v2^2 = v1^2 + 2ah, with v1 = vy = 20*sin(60), and a = g
\n" ); document.write( "h = vy^2/2g
\n" ); document.write( "I assume total hang time refers to the time the ball takes to hit the ground.
\n" ); document.write( "The time to reach maximum height is determined from v2 = v1 + at,
\n" ); document.write( "with v2 = 0. Thus t = vy/g
\n" ); document.write( "The time to fall from the maximum height to the ground is determined from
\n" ); document.write( "h + h0 = v1t + 1/2at^2. Since v1 = 0, we have t = sqrt(2(h + h0)/g)
\n" ); document.write( "Now for the final velocity, we need to determine the x and y components
\n" ); document.write( "vx will remain constant throughout, and is equal to 20*cos(60)
\n" ); document.write( "The y component of the final velocity is obtained from v2^2 = v1^2 + 2a(h+h0)
\n" ); document.write( "with v1 = 0
\n" ); document.write( "I will leave it to you to fill in the values and get the final numbers
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