document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170980>Question 1170980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perla is 28 years old who has a daughter 4 years old. In how many years will her daughter be 1/3 her age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795849 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of years<BR>\n" );
document.write( "28+x 3(4+x), since Perla will be 3 times older than her daughter<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "28 + x = 12 + 3x<BR>\n" );
document.write( "2x = 16 -> x = 8<BR>\n" );
document.write( "Check: 28 + 8 = 3(4+8)<BR>\n" );
document.write( "36 = 3*12 YES\r<BR>\n" );
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document.write( " </SPAN>\n" );
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