document.write( "Question 1170941: The bird capable of the fastest flying speed is the swift. A swift flying with the wind to a favorite feeding spot traveled 36 mi in 0.3 h. On returning, now against the wind, the swift was able to travel only 21 mi in the same amount of time. What is the rate of the swift in calm air, and what was the rate of the wind? \n" ); document.write( "

Algebra.Com's Answer #795816 by ikleyn(52794) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "The effective rate with the wind is   = 120 mph,  and it is the sum \r\n" );
document.write( "of the swift rate in calm air and the rate of the wind\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    u + v = 120  mph    (1)\r\n" );
document.write( "\r\n" );
document.write( "   \r\n" );
document.write( "\r\n" );
document.write( "The effective rate against the wind is   = 70 mph,  and it is the difference \r\n" );
document.write( "of the swift rate in calm air and the rate of the wind\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    u - v =  70  mph.   (2)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Adding equations (1) and (2), you find  u = 95 mph  for the rate of the swift in calm air.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Subtracting equations (1) and (2), you find  v = 25  mph  for the rate of wind.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );