document.write( "Question 1170895: Foci at (2, 3) and (2, -1), endpoint of minor axis (4, 1). Find the equation of the ellipse and sketch the graph. \n" ); document.write( "
Algebra.Com's Answer #795815 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Equation of the ellipse in standard form: \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\" ...horizontal major axis (\"a%3Eb\")\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1+\" ...vertical major axis (\"a%3Eb\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "given Co-vertices:(\"4\",\"1\")->means we have \"vertical\" major axis\r
\n" ); document.write( "\n" ); document.write( "so, you need\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "given foci at (\"2\",\"+3\") and (\"2\",\"+-1\") \r
\n" ); document.write( "\n" ); document.write( "then center is half way between\r
\n" ); document.write( "\n" ); document.write( "center: (\"%282%2B2%29%2F2\",\"%283-1%29%2F2\")=(\"2\",\"1\")\r
\n" ); document.write( "\n" ); document.write( "distance between foci and center is \"c\" and -> \"c=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Co-vertices: given one at (\"4\",\"1\")\r
\n" ); document.write( "\n" ); document.write( "distance from center (\"2\",\"1\") is \"d=sqrt%28%284-2%29%5E2%2B%281-1%29%5E2%29=sqrt%282%5E2%2B0%29=2\"\r
\n" ); document.write( "\n" ); document.write( " the other one is at (\"x\",\"1\") same distance from center
\n" ); document.write( " (\"2-2\",\"1\")=(\"0\",\"1\")\r
\n" ); document.write( "\n" ); document.write( "Minor axis length: \"b=4\"
\n" ); document.write( "Semiminor axis length: \"2\"\r
\n" ); document.write( "\n" ); document.write( "now we can calculate \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"a=sqrt%284%5E2-2%5E2%29\"
\n" ); document.write( "\"a=sqrt%2816-4%29\"
\n" ); document.write( "\"a=sqrt%288%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "then your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"%282-x%29%5E2%2F4%2B%28y-1%29%5E2%2F8=1+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );