document.write( "Question 1170913: Using 1 lb. of lead, and allowing 5% for waste, determine amount of shot 1/16 in. in diameter that can be produced.\r
\n" ); document.write( "\n" ); document.write( " Lead weighs .410 lbs. per cu. in.\r
\n" ); document.write( "\n" ); document.write( " Lead shot are spheres.\r
\n" ); document.write( "\n" ); document.write( " Sphere volume = 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( " 1.333 * 3.1416 * .03125 * .03125 * .03125 = .0001278 cu. in.\r
\n" ); document.write( "\n" ); document.write( " 5% waste = .95 lb. remaining.\r
\n" ); document.write( "\n" ); document.write( " Not sure how to proceed.
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Algebra.Com's Answer #795810 by Alan3354(69443)\"\" \"About 
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Using 1 lb. of lead, and allowing 5% for waste, determine amount of shot 1/16 in. in diameter that can be produced.\r
\n" ); document.write( "\n" ); document.write( " Lead weighs .410 lbs. per cu. in.\r
\n" ); document.write( "\n" ); document.write( " Lead shot are spheres.\r
\n" ); document.write( "\n" ); document.write( " Sphere volume = 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( " 1.333 * 3.1416 * .03125 * .03125 * .03125 = .0001278 cu. in.\r
\n" ); document.write( "\n" ); document.write( " 5% waste = .95 lb. remaining.\r
\n" ); document.write( "\n" ); document.write( " Not sure how to proceed.
\n" ); document.write( "===================================
\n" ); document.write( " Sphere volume = 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( " 1.333 * 3.1416 * .03125 * .03125 * .03125 = .0001278 cu. in.
\n" ); document.write( "Mass of each sphere = .0001278 cu. in. * .410 lbs. per cu. in.
\n" ); document.write( "=~ 5.2398e-5 pounds per piece.
\n" ); document.write( "===============
\n" ); document.write( "0.95/5.2398e-5 = 18,130 spheres
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