document.write( "Question 1170811: Two hikers, Juan and Pedro started from the same place at the same time towards Arayat which is 90 kilometers away from their place. Pedro traveled 1 kilometer per hour faster than Juan and reached Arayat 1 hour before him. Find the rate of each hiker \n" ); document.write( "
Algebra.Com's Answer #795775 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Two hikers, Juan and Pedro started from the same place at the same time towards Arayat which is 90 kilometers away from their place. \n" ); document.write( " Pedro traveled 1 kilometer per hour faster than Juan and reached Arayat 1 hour before him. \n" ); document.write( " Find the rate of each hiker \n" ); document.write( ": \n" ); document.write( "let j = Juan's hiking rate \n" ); document.write( "then \n" ); document.write( "(j+1) = Pedro's hiking rate \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/rate \n" ); document.write( ": \n" ); document.write( "J's time - P's time = 1 hr \n" ); document.write( " \n" ); document.write( "multiply equation by j(j+1), cancel the denominators \n" ); document.write( "90(j+1) - 90j = j(j+1) \n" ); document.write( "90j + 90 - 90j = j^2 + j \n" ); document.write( "arrange as quadratic equation \n" ); document.write( "j^2 + j - 90 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(j+10)(j-9) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "j = 9 mph is J's hiking rate \n" ); document.write( "then, obviously, 10 km/h is Pedro's \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "90/9 - 90/10 = \n" ); document.write( "10 - 9 = 1 \n" ); document.write( " |