document.write( "Question 1170876: Find the missing coordinate of P, using the fact that P lies on the unit circle in the given quadrant.
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Algebra.Com's Answer #795757 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Coordinates ....|.... Quadrant
\n" ); document.write( "\"P\"(\"x\" , \"-5%2F7\") ....|.... \"+IV\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+%28-5%2F7%29%5E2+=+1%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+25%2F49+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+++=+1+-25%2F49\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+++=+24%2F49\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+sqrt%2824%2F49%29\".........The sign is \"+\" (plus) at sqrt operator, because the point is in Quadrant IV\r
\n" ); document.write( "\n" ); document.write( "\"x=%282sqrt%286%29%29%2F7+\"->exact solution\r
\n" ); document.write( "\n" ); document.write( "\"P\"(\"%282sqrt%286%29%29%2F7\", \"-5%2F7\") \r
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