document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170861>Question 1170861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello i need ASAP help can someone please answer <BR>\n" );
document.write( "Steve is a jeweller who wants to create rings of a certain gold purity. 24-kt (karat) is considered<BR>\n" );
document.write( "pure gold. Steve has a stock of 18-kt and 10-kt on hand. He wants to have 200g of 16-kt gold. How much<BR>\n" );
document.write( "18-kt and 10-kt does he need to have a 200g sample? <BR>\n" );
document.write( "thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795752 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You have received, to this point, two formal algebraic solutions.  One uses a typical approach and gets to an answer relatively quickly.  The other uses a very roundabout approach, eventually reaching an answer.<br><BR>\n" );
document.write( "If a formal algebraic solution method is not required, here is the fastest and easiest way to get the answer.<br><BR>\n" );
document.write( "You are mixing 10-kt and 18-kt gold to get 16-kt gold.<BR>\n" );
document.write( "Consider the three numbers on a number line.  16 is 3/4 of the way from 10 to 18.<BR>\n" );
document.write( "That means 3/4 of the mixture needs to be the 18-kt gold.<br><BR>\n" );
document.write( "ANSWER: 3/4 of 200g, or 150g, is the 18-kt gold; the other 50g is the 10-kt gold.<br><BR>\n" );
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