document.write( "Question 1170866: the perimeter of a rectangle is 30 meters. twice its length is the same as thrice its width. find its dimensions. \n" ); document.write( "
Algebra.Com's Answer #795749 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 2L + 2W = 30 meters (1)\r\n" ); document.write( "\r\n" ); document.write( " 2L = 3W (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In equation (1), replace 2L by 3W, based on (2). You will get\r\n" ); document.write( "\r\n" ); document.write( " 3W + 2W = 30\r\n" ); document.write( "\r\n" ); document.write( " 5W = 30\r\n" ); document.write( "\r\n" ); document.write( " W = 30/5 = 6.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The dimensions are 6 meters (the width) and 9 meters (the length).\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |