document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170809>Question 1170809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 6500 bacteria. After 2.5 hours,there are 208000 bacteria present. What is the length of the doubling period?..SHOW WORK. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795706 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 208000=6500(1+r)^n<BR>\n" );
document.write( "divide by 6500<BR>\n" );
document.write( "32=(1+r)^n<BR>\n" );
document.write( "actually, 2^5=32<BR>\n" );
document.write( "so r has to be 1 and n=5\r<BR>\n" );
document.write( "\n" );
document.write( "but n=5 means 2.5 hours, so the doubling period is every 30 minutes or half hour.<BR>\n" );
document.write( "13K<BR>\n" );
document.write( "26K<BR>\n" );
document.write( "52K<BR>\n" );
document.write( "104K<BR>\n" );
document.write( "208K </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );