document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170824>Question 1170824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radioactive element decays at a rate of 19% / year. Initially, there is 10,000 lbs of this material. How much will be left after 21 years? (round to two decimal places)\r<BR>\n" );
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document.write( "	A.7.14 lbs\r<BR>\n" );
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document.write( "	B.About zero lbs\r<BR>\n" );
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document.write( "	C.Solution not listed\r<BR>\n" );
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document.write( "D.119.73 lbs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795700 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This would be 10000(0.81)^21. The 0.81 is the amount left of the previous year with each passing year<BR>\n" );
document.write( "=119.73 lbs.<BR>\n" );
document.write( "D </SPAN>\n" );
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