document.write( "Question 1170773: Twice Mae's age added to Nora's age is 35. Five years ago, Nora was twice as old as Mae was then. Find the current age of each.
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Algebra.Com's Answer #795690 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Twice Mae's age added to Nora's age is 35. Five years ago, Nora was twice as old as Mae was then. Find the current age of each.
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Let Mae's age be M
\n" ); document.write( "Then, 2M + Nora's age = 35 ======> Nora = 35 - 2M
\n" ); document.write( "We then get: 35 - 2M - 5 = 2(M - 5)
\n" ); document.write( " 30 - 2M = 2M - 10
\n" ); document.write( " - 2M - 2M = - 10 - 30
\n" ); document.write( " - 4M = - 40
\n" ); document.write( " Mae, or
\n" ); document.write( "You can now find Nora's age! \n" ); document.write( "
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