document.write( "Question 1170807: The salaries of the employees in a company follow the normal distribution with mean $16000 and standard deviation $800.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the probability that the salary of an employee is higher than $18000? \r
\n" ); document.write( "\n" ); document.write( "(b) There is 80% chance that the salary of an employee is less than $t. Find the value of t. \r
\n" ); document.write( "\n" ); document.write( "(c) If 20 employees are randomly chosen from the company and the mean salary of the employees is calculated. The manager of the company claims that over 20% of the mean salaries of the employee are higher than $16200. Do you agree?
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Algebra.Com's Answer #795685 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "z > (18000-16000)/800 or 2.5
\n" ); document.write( "that probability is 0.0062
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\n" ); document.write( "z (0.80)=0.8416
\n" ); document.write( "0.8416=(t-16000)/800
\n" ); document.write( "673.29=t-16000, will round to nearest integer
\n" ); document.write( "t=$16,673.
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\n" ); document.write( "z=(16200-16000)/800/sqrt(20)
\n" ); document.write( "-200*sqrt(20)/800=.
\n" ); document.write( "=1.118
\n" ); document.write( "That probability of z> than that value is 13.2%
\n" ); document.write( "The sd of the sampling distribution with n=20 has mean $16000 as before, but sd is 178.88
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