document.write( "Question 1170801: Solve the following problems by using elimination or substitution. Make sure to define your variables, write a system, solve showing all work and write a complete sentence answer.\r
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document.write( "Robert has a job offer in which he will receive $900 a month plus a commission of 4.5% of the total price of the cars that he sells. His current job pays him $1200 a month plus a commission of 3.25% of the total price of the cars that he sells. How many sales would he need each month to make the new job a better deal?\r
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Algebra.Com's Answer #795684 by Theo(13342)![]() ![]() You can put this solution on YOUR website! new job = 900 a month plus 4.5% of the sales. \n" ); document.write( "old job = 1200 a month plus 3.25% of the sales.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation for new job is y = .045 * x + 900 \n" ); document.write( "equation for old job is y = .0325 * x + 1200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you want to know when the new job gives him better total compensation than the old job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this occurs when .045 * x + 900 > .0325 * x + 1200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 900 from both sides of the inequality and subtract .0325 * x from both sides of the inequality and simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".0125 * x = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 300 / .0125 = 24,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the new job will provide better compensation than the old job when sales exceed 24,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to confirm, select sales lower than 24,000, higher than 24,000, and equal to 24,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i picked 20,000, 30,000 and 24,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 20,000 sales, new job pays 900 + .045 * 20,000 = 1800 and old job pays 1200 + .0325 * 20,000 = 1850. \n" ); document.write( "old job pays better.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 30,000 sales, new job pays 900 + .045 * 30,000 = 2250 and old job pays 1200 + .0325 * 30,000 = 2175. \n" ); document.write( "new job pays better.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 24,000 sales, new job pays 900 + .045 * 24,000 = 1980 and old job pays 1200 + .0325 * 24,000 = 1980. \n" ); document.write( "they pay the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can graph these equations. \n" ); document.write( "the graph will show you where the break even point is and when the new job starts paying more than the old job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph is shown below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "red is the new job, blue is the old job.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |