document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1170748>Question 1170748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 35% and the third contains 65%. He wants to use all three solutions to obtain a mixture of 64 liters containing  <BR>\n" );
document.write( "45% acid, using 2 times as much of the 65% solution as the 35% solution. How many liters of each solution should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #795639 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=795639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x liters of .15 or .15x pure acid<BR>\n" );
document.write( "y liters of .35 or .35y pure acid<BR>\n" );
document.write( "2y liters of .65 or 1.3y pure acid<BR>\n" );
document.write( "total amount is 64 liters of .45 acid or 28.8 liters of pure acid<BR>\n" );
document.write( "x+3y=64 liters<BR>\n" );
document.write( ".15x+1.65y=28.80 <BR>\n" );
document.write( "15x+45y=960<BR>\n" );
document.write( "15x+165y=2880 subtract second<BR>\n" );
document.write( "-120y=-1920<BR>\n" );
document.write( "y=16 liters of .35 (5.6 l per acid)<BR>\n" );
document.write( "2y=32 l of .65 (20.8)<BR>\n" );
document.write( "x=16 l of .15 (2.4)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );