document.write( "Question 1170709: Hi, I need help
\n" ); document.write( "A cube is expanding in such a way that its sides are changing at a rate of
\n" ); document.write( "2 cm s^( - 1). Find the rate of change of the total surface area when its volume is 125 cm^3.
\n" ); document.write( "

Algebra.Com's Answer #795598 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "The surface area of a cube is  S(a) = 4a^2,  where \"a\" is the edge size.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "We have edge size depending on time  a = a(t);  therefore, the rate of the surface area change is the derivative\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    S'(t)  =  4*2*a(t)*a'(t)  =  8*a(t)*a'(t)  \"cm%2A%28cm%2Fs%29\".     (1)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The value a'(t) is given : it is  a'(t) = 2 cm/s.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The value of \"a\" is a= 5, when the volume is 125 cm^3.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Therefore,  the rate of the surface area change is, according the formula (1), \r\n" );
document.write( "\r\n" );
document.write( "    S'(t) = 8*5*2 = 80 \"cm%5E2%2Fs\".     ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved,  answered and explained.   And completed.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );