document.write( "Question 1170676: A pond is a half acre and is frozen over. The depth of ice covering pond is 2 in. Determine weight of ice. Ice weighs 57.4 lbs. per cu. ft.\r
\n" ); document.write( "\n" ); document.write( "Half acre = 21780 sq. ft.\r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve.
\n" ); document.write( "

Algebra.Com's Answer #795563 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "given:
\n" ); document.write( "A pond is a half acre and is frozen over.
\n" ); document.write( "The depth of ice covering pond is \"2in\".
\n" ); document.write( "Ice weighs \"57.4lb\". per \"cu.+ft\".
\n" ); document.write( "Half acre = \"21780ft%5E2\".\r
\n" ); document.write( "\n" ); document.write( "we need a volume of ice
\n" ); document.write( "\"2in\" ocvert to ft: \"2in=%282%2F12%29ft=%281%2F6%29ft\"
\n" ); document.write( "\"21780ft%5E2%281%2F6%29ft=%2821780%2F6%29ft%5E3=3630ft%5E3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since ice weighs \"57.4lb%2Fft%5E3\". per \"cu.+ft\", we have\r
\n" ); document.write( "\n" ); document.write( "\"%2857.4lb%2Fcross%28ft%5E3%29%29%2A3630cross%28ft%5E3%29=57.4lb%2A3630=208362lb\"\r
\n" ); document.write( "\n" ); document.write( " the weight of ice is \"208362lb\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );